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A math shit, help pls

| 4(x+1)(4x+1)=0
(x+1)^2=0
(x+1)=0
x+1=0
x=-1

Where did the number 4 go????


| first 4 got divided out (0/4=0)
second 4 dont make sense.
(x+1)^2 = x^2+2x+1
NOT (x+1)(4x+1)
thats wrong.


| >>969738
Why for got dived out?


| 4


| >>969720

4(x+1)(4x+1)=0

(4x+4)*(16x+4)=0

(1x+1)*(4x+1)=0

4x²+1x+4x+1=0

16x+1x+4x+1=0

21x+1=0

21x=-1

x=-0.047619046619


| *..7619


| >>969720 x = -1, -1/4

Here is the calculator that can help you, kid.

https://www.mathway.com


| >>969999
This is hilariously wrong lmao


| >>969965
You move the 4 to the right side
4(x+1)(4x+1) = 0
(x+1)(4x+1) = 0/4
(x+1)(4x+1) = 0


| 76


| It's 69


| >>970241 i work in CERN, trust me


| >>970307 As a janitor?


| >>970243 btw your logic is totally wrong even if math worked like this than:

x+1+1+4 = 4 * 4 * () * ()
x+6=16*0*0
x=10*0*0
x=0
4x=4
x=44
4x=44
x=444
x=444444...4


| >>970308 no, i do math in quantum physics department


| >>970309 Is this a joke? If it is not a joke, then there is no concern that CERN does nothing grate those days...

Total number of posts: 16, last modified on: Sun Jan 1 00:00:00 1692762271

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